Conversion program from number to words

Question:

Write a program to convert the number to words.

Logic:

• Get the input number from the user.
• Then check the number with the individual digits with ones, tens, hundreds and so on.
• And then print corresponding words for the numbers.

Algorithm:

1. The numbers in words are stored in the array.
2. Then checks the number with their position.
3. For its ones, tens, hundreds and so on.
4. Then print corresponding words for the corresponding numbers in the array.

Program:

include<stdio.h>
void main()
{
	int i,k=0,a,b[7],c,d,num;
	char *ones[]={"one","two","three","four","five","six","seven","eight","nine"};
	char *tens[]={"eleven","twelve","thirteen","fourteen","fifteen","sistenn","seventeen","eighteen","nineteen"};
	char *rou[]={"ten","twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninty"};
	clrscr();
	printf("enter the number within 6 digits:lessthan 32767:");
	scanf("%d",&num);
	while(num>0)                                          // seperates the dits  and stores into the array
	{
		a=num%10;
		b[k]=a;
		k++;
		num=num/10;
	}
	for(i=k-1;i>=0;i--)
	{
		if(i==4)                                       // prints the thousands
		{
			c=b[i];
			d=b[i-1];
			if(b[i-1]==0)
			{
				printf("%s thousand ",rou[c-1]);
			}
			else if(c>1)
			{
				printf("%s %s thousand ",rou[c-1],ones[d-1]);
			}
			else
			{
				printf("%s thousand ",tens[d-1]);
			}
		}
		if(i==3&&b[i]!=0&&k==4)                        //also prints the thousands <10000
		{
			c=b[i];
			printf("%s  thousand ",ones[c-1]);
		}
		if(i==2&&b[i]!=0)                             //prints the hundreds
		{
			c=b[i];
			printf("%s  hundred ",ones[c-1]);
		}
		if(i==1&&b[i]!=0)                            // prints the tens
		{
			c=b[i];
			d=b[i-1];
			if(b[i-1]==0)
			{
				printf("%s ",rou[c-1]);
			}
			else if(c>1)
			{
				printf("%s %s ",rou[c-1],ones[d-1]);
			}
			else
			{
				printf("%s ",tens[d-1]);
			}
		}
		if(i==0&&b[i]!=0&&k==1)                     //prints the ones
		{
			c=b[i];
			printf("%s",ones[c-1]);
		}
		if(b[i]==0&&k==1)
		{
			printf("zero");
		}
	}
	getch();
}