To print all palindromes present in a word

This program can able to print all palindromes present in a word and also its count.

Logic:

• Get the input string from the user.
• Then compare one character with all other characters.
• If the character is matching take it as a word.
• And check the word whether it is palindrome or not.

Algorithm:

1. Get the input string from the user.
2. Compare one element with all other elements in the string.
3. When the elements are matching take the complete length as a string.
4. Then check the word with palindrome matching.
5. And print all palindromes present in the word.

Program:

#include<stdio.h>
void main()
{
	int n,i,j,k,b,count=0,l,e,g;
	char a[20];
	clrscr();
	printf("enter the string:");
	gets(a);
	n=strlen(a);
	if(n==1)
	{
		printf("The palindrome is:%c",a[0]);
		printf("\n");
	}/*each element checks with all other elements and if they matches then check whether it is palindrome or not*/
	for(i=0;i<n;i++)
	{        l=i+1;
		for(j=i;l<n;)
		{
		    if(a[j]==a[l])//if one element equals with other
		    {         e=l;
				for(k=j;k<=l;k++)//checks palindrome or not
				{
					if(a[k]!=a[e])
					{
						break;
					}
					if(k>=(l+1)/2)// print the palindrome strings
					{       
						count++;//count no of palindrome 
						printf("The palindromes are:");
						for(g=j;g<=l;g++)
						{
							printf("%c",a[g]);
						}
						printf("\n");
						break;
					}
					e--;
				}
		    } l++;
		}
	}
	printf("No of palindrome is:%d",count);
	getch();
}