# Program to Perform Arithmetic Operations Without Using Arithmetic Operators in C

**Question**

It is one of most frequently asked interview question to perform any arithmetic operations(add,subtract,multiply,divide) without using arithmetic operators.

*Logic*

- The logic is simple. We have to use loop and manipulate the value of one variable with value of another variable. This will help us calculate the addition and subtraction.
- Nested loops can help us to perform Division and multiplication. We perform same addition/ subtraction operation more number of times to get the result.

### Program:

#include <stdio.h> //Compiler version gcc 6.3.0 //Program to perform arithmetic operations //Without arithmetic operator int main() { int a,b,c,i=0,j=0,t=0,temp; //intialization for using in below programs int n; // initialize for switch printf("Enter First Value\n"); scanf("%d",&a); // read value 1 printf("Enter Second Value\n"); scanf("%d",&b);// read value 2 printf("Choose Operation:\n"); printf("1.ADD\n2.SUBTRACT\n3.MULTIPLE\n4.DIVIDE\n"); scanf("%d",&n);// read integer for switch case /* Before move to perform operation, we should change the big value to variable a and small value to variable b. Its minimize the execution time. */ //Swapping function if(a<b) { t=b; b=a; a=t; } switch(n) { case 1: //for addition operation while(b>i) // check b(low value) with i { a++; //increment once i++; //increment i } // the loop execute until the b equals to i and a was incremented. //now the value of a is equal to a+b printf("%d",a); break; case 2://for subtraction operation while(b>i) // check b(low value) with i { a--;//decrement once i++; //increment i }// the loop execute until the b equals to i and a was incremented. //now the value of a is equal to a-b printf("%d",a); break; case 3://for multiplication operation temp=a; //in that time we use same addition loop with a times.so we use nested loop. i=1; while(b>i) { while(temp>j) { a++; j++; } j=0; i++; } printf("%d",a); break; case 4: //for division operation i=0;c=0; t=b; //in that time we use same subtraction loop with a times.so we use nested loop. while(a>t) { while(b>i) { a--; i++; } i=0; c++; //we count the number of times subtracted } printf("%d",c+1); //print the last count of subtraction value break; break; } return 0; }

Keywords:

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Program to Perform Multiplication Operation without Arithmetic Operators

Program to Perform Division Operation without Arithmetic Operators