TCS NQT Set 1 | Day 1 2020 | keyword or not

TCS NQT Set 1 | Day 1 2020 | keyword or not

TCS NQT Set 1 | Day 1 2020 | keyword or not

One programming language has the following keywords that cannot be used as identifiers:

break, case, continue, default, defer, else, for, func, goto, if, map, range, return, struct, type, var

Write a program to find if the given word is a keyword or not

Logic:

  • Get the input string from the user
  • Then compare all given keywords like break, case, continue, default, defer, else, for, func, goto, if, map, range, return, struct, type and var using strcmp() function
  • Then print the output whether the keyword is found or not

TCS NQT Set 1:

Program:

[code lang=”c”]
#include<stdio.h>
#include<string.h>
void main()
{
char a[30];
scanf("%s",&a);
//compare the sting with all keywords
if((strcmp(a,"defer")==0)||(strcmp(a,"if")==0)||(strcmp(a,"for")==0)||(strcmp(a,"return")==0)||(strcmp(a,"break")==0)(strcmp(a,"case")==0)||(strcmp(a,"continue")==0)||(strcmp(a,"default")==0)||(strcmp(a,"else")==0)||(strcmp(a,"func")==0)||(strcmp(a,"goto")==0)||(strcmp(a,"map")==0)||(strcmp(a,"range")==0)||(strcmp(a,"struct")==0)||(strcmp(a,"type")==0)||(strcmp(a,"var")==0))
{
printf("%s is a keyword",a);
}
else //print when keyword not matching
{
printf("%s is not a keyword",a);
}
}
[/code]

You might also  like:

Set 2 | Day 1 2020

Set 3 | Day 1 2020

Set 4 | Day 1 2020

Vignesh

A Computer Science graduate who likes to make things simpler. When he’s not working, you can find him surfing the web, learning facts, tricks and life hacks. He also enjoys movies in his leisure time.

Leave a Reply

Your email address will not be published. Required fields are marked *